Since the probability of the faces are proportional to the numbers on them, we can take the probabilities of faces 1,2,...,6 as k,2k,....,6k, respectively.
Since one of the faces must occur, we have
k+2k+3k+4k+5k+6k=1⇒k=121
Therefore, the probability of occurence of an even number is 2k+4k+6k=12k=1221=47