Question

A die is rolled $6$ times which results in the outcomes as $1,3,3,3,4,4$. Match the followings:

• A. $\frac{1}{2}$
• B. $\frac{1}{6}$
• C. $\frac{1}{3}$

Answer 1

Given:
Total number of trials = $6$

Event	Frequency
Rolling 1	1
Rolling 3	3
Rolling 4	2

Therefore,
$\text{P (1)}=\frac{\text{Frequency of rolling 1}}{\text{Total trials}}=\frac{1}{6}$

$\text{P (3)}=\frac{\text{Frequency of rolling 3}}{\text{Total trials}}=\frac{3}{6}=\frac{1}{2}$

$\text{P (4)}=\frac{\text{Frequency of rolling 4}}{\text{Total trials}}=\frac{2}{6}=\frac{1}{3}$