Question

A die is rolled, then the probability that a number 1 or 6 may appear is

• A. $\frac{2}{3}$
• B. $\frac{5}{6}$
• C. $\frac{1}{3}$
• D. $\frac{1}{2}$

Answer 1

The correct option is C

$\frac{1}{3}$

Total number of sample space,

S = {1, 2, 3, 4, 5, 6}

$\therefore$ n(S) = 6

Let A be the event of getting the number 1 or 6

A = {1, 6}

i.e., n(A) = 2

Hence, required probability $=\frac{n\left(A\right)}{n\left(S\right)}$

$=\frac{2}{6}=\frac{1}{3}$