Question

A die is rolled three times. The probability of getting a large number than the previous number each times is

• A. $\frac{15}{216}$
• B. $\frac{5}{54}$
• C. $\frac{13}{216}$
• D. $\frac{1}{18}$

Answer 1

The correct option is B $\frac{5}{54}$

Total number of possible out come$=6^3=216$

Now, we can choose any three numbers out of $6$ numbers and we can place them in ascending order in only one way.

So, favourable out come$={}^6{C}_3=20$

Now, probability$=\frac{20}{216}=\frac{5}{54}$.