Question

A die is rolled three times, the probability of getting a large number then the previous number is

• A. $\frac{5}{216}$
• B. $\frac{5}{54}$
• C. $\frac{1}{6}$
• D. $\frac{5}{36}$

Answer 1

Answer: (B)

$\frac{5}{54}$

Since only one permutation will be strictly increasing of the 6 possible from 3 numbers this means that: € P = 1 3! ⋅ (6)3 63 = 6 3 # $ % & ' ( 63 = 20 216 = 5/54