Question

a die is rolled thrice, find its probability of getting a larger number each time than the previous number.

Answer 1

Here is the solution:
Here total number of possible out come = $6^3=216$
Now, we can choose any three numbers out of 6 numbers and we can place them in ascending order in only one way.
So, favourable out come = ${}^{6}C_3=20$
Now, probability = $\frac{20}{216}=\frac{5}{54}$