Question

a die is so biased that each odd number is twice as likely to occur as each even number. if a die is thrown once. what is the probability of getting an even number?

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{probability}\mathrm{of}\mathrm{even}=\mathrm{p} \\ \mathrm{So}\mathrm{probability}\mathrm{of}\mathrm{getting}\mathrm{odd}\mathrm{number}=2\mathrm{p} \\ \mathrm{p}+2\mathrm{p}=1 \\ \mathrm{p}=\frac{1}{3} \\ \mathrm{SO}\mathrm{the}\mathrm{probability}\mathrm{of}\mathrm{even}=\frac{1}{3} \\ \mathrm{and}\mathrm{probability}\mathrm{of}\mathrm{getting}\mathrm{odd}\mathrm{number}=\frac{2}{3} \\ \mathrm{If}\mathrm{dice}\mathrm{is}\mathrm{thrown}\mathrm{once}\mathrm{then}\mathrm{probability}\mathrm{of}\mathrm{getting}\mathrm{an}\mathrm{even}\mathrm{number} \\ =\frac{1}{3} \end{gathered}$$