A die is thrown $200$ times and the outcomes $1, 2, 3, 4, 5, 6$ have frequencies as below:

Outcome

$1$

$2$

$3$

$4$

$5$

$6$

Frequency

$40$

$38$

$43$

$29$

$28$

$22$

Find the probabilities of getting a number more than $1$ and less than $6$ in a toss (trial).

0.65

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0.55

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0.69

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None of these

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Solution

The correct option is D $0.69$
Since, Total cases $= 200$
Getting a no. more than $1$ and less than $6 (2, 3, 4, 5) = 38 + 43 + 29 + 28 = 138$
$∴$ probability $=$ $\frac{138}{200} = 0.69$

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A die is thrown 500 times and the outcomes 1, 2, 3, 4, 5, 6 have frequencies as given below

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80

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A die is thrown 500 times and the outcomes 1, 2, 3, 4, 5, 6 have frequencies as given below

$\begin{matrix} O u t c o m e & 1 & 2 & 3 & 4 & 5 & 6 F r e q u e n c y & 75 & 85 & 90 & 80 & 75 & 95 \end{matrix}$

What is the probability of getting a value greater than or equal to 4?

A die is thrown 1000 times with the following frequency for the outcomes 1, 2, 3, 4, 5 and 6 as given below :

$\begin{matrix} Outcome & 1 & 2 & 3 & 4 & 5 & 6 frequency & 179 & 150 & 157 & 149 & 175 & 190 \end{matrix}$

(i) Find the probability of getting a 1 or a 6
(ii) Find the probability of getting a multiple of 4 [ 2 MARKS]

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