Question

A die is thrown 325 times. The frequency of the outcomes of the event 1, 2, 3, 4, 5 and 6 are recorded in the following frequency distribution table.

$\begin{array}{ccccccc}\text{Outcome}& 1& 2& 3& 4& 5& 6\\ \text{Frequency}& 50& 65& 45& 34& 55& 76\end{array}$

Find the probability of the occurrence of an (i) even number (ii) odd number.

• A. $\frac{7}{13}$ and $\frac{6}{13}$
• B. $\frac{7}{13}$ and $\frac{8}{11}$
• C. $\frac{11}{20}$ and $\frac{6}{13}$
• D. $\frac{11}{25}$ and $\frac{7}{10}$

Answer 1

The correct option is A

$\frac{7}{13}$ and $\frac{6}{13}$

Probability = $\frac{Numberoffavourableoutcomes}{Totalnumberofoutcomes}$


Total no. of outcomes = 325

Frequency of getting an even number = 65 + 34 + 76 = 175

Frequency of getting an odd number = 325 - 175 = 150

P (Even Number) $=\frac{175}{325}=\frac{7}{13}$

P (Odd Number) $=\frac{150}{325}=\frac{6}{13}$