Question

A die is thrown 500 times and the outcomes 1, 2, 3, 4, 5, 6 have frequencies as given below

$\begin{array}{ccccccc}\text{Outcome}& 1& 2& 3& 4& 5& 6\\ \text{Frequency}& 75& 85& 90& 80& 75& 95\end{array}$

What is the probability of getting a value greater than or equal to 4?

• A. 0.6
• B. 0.75
• C. 0.5
• D. 0.8

Answer 1

The correct option is C 0.5

Let E denote the event of getting the outcome of greater than or equal to 4.

Number of trials in which the event happened
= Number of times a value greater than or equal to 4 occured
= 80 + 75 + 95
= 250

Therefore,
$P\left(E\right)=\frac{\text{Number of trials in which the event happened}}{\text{Total number of trials}}⟹P\left(E\right)=\frac{250}{500}=0.5$