Question

A die is thrown 6 times. If ‘getting an odd number’ is a success, then the probability of 4 successes is

• A. $\frac{15}{64}$
• B. $\frac{35}{64}$
• C. $\frac{13}{64}$
• D. $\frac{1}{4}$

Answer 1

The correct option is A $\frac{15}{64}$

given $n=6,p=0.5,q=0.5\&r=4$
so $P(4$ successes)$={}^6{C}_4\left(0.5{)}^4\right(0.5{)}^2=\frac{15}{64}$