When a die is thrown , the possible outcomes are 1,2,3,4,5 or 6.
So, U=S={1,2,,4,5,6}
(i) A={1,2,3,4,5,6}
(ii)B=ϕ
(iii)C={3,6}
(iv)D={1,2,3}
(v)E={6}
(vi)F={4,5,6}
Now, A∪B={1,2,3,4,5,6}
A∩B=ϕ
B∪C={3,6}
E∩F={6}
D∩E=ϕ
A−C={1,2,4,5}
D−E={1,2,3}
E∩F′=E−F=ϕ
F′=U−F={1,2,3}