Question

A die is thrown. Find the probability of getting :

(i) a prime number (ii) 2 or 4 (iii) a multiple of 2 or 3

Answer 1

Total number of possible events = 6(1 to 6)

(i) Let A be the favourable occurence which are prime number i.e., 2,3,5

$\therefore P\left(A\right)=\frac{3}{6}=\frac{1}{2}$

(ii) Let B be the favourable occurence which are 2 or 4

$\therefore P\left(B\right)=\frac{2}{6}=\frac{1}{3}$

(iii) Let C be the favourable occurence which are multiple of or 3 i.e., 2,3,4,6.

$\therefore P\left(C\right)=\frac{4}{6}=\frac{2}{3}$