Question

A die is thrown, Find the probability of getting:

(i) a prime number

(ii) 2 or 4

(iii) a multiple of 2 or 3

(iv) an even prime number

(v) a number greater than 5

(vi) a number lying between 2 and 6

(vii) a composite number

Answer 1

Total number on a dice is 6.

(i) Prime number on a dice are 2,3,5

Total number of prime numbers on dice is 3

We know that PROBABILITY =

Hence probability of getting a prime number =

(ii) for getting 2 and 4 favorable outcome are 2

We know that PROBABILITY =

Hence probability of getting 2 or 4 =

(iii) Multiple of 2 are 3 are 2, 3, 4 and 6

Hence favorable outcome is 4

We know that PROBABILITY =

Hence probability of getting an multiple of 2 or 3 =

(iv) an even prime number is 2

Hence favorable outcome is 1

We know that PROBABILITY =

Hence probability of getting an even prime number

(v) A number greater than 5 is 6

Hence favorable outcome is 1

We know that PROBABILITY =

Hence probability of getting a number greater than 5

(vi) Total number on a dice is 6.

Number lying between 2 and 6 are 3, 4 and 5

Total number of number lying between 2 and 6 is 3

We know that PROBABILITY =

Hence probability of getting a number lying between 2 and 6 =
(vii) The composite numbers on a die are 4 and 6.

Favourable number of events = Total number of composite numbers on a die = 2

Total number of events = 6

We know that PROBABILITY =

Hence probability of getting a composite number = $\frac{2}{6}=\boxed{\frac{1}{3}}$