Question

A die is thrown. Let $A$ be the event that the number obtained is greater than $3$. Let $B$ be the event that the number obtained is less than $5$. Then $(A\cup B)$ is

• A. $\frac{2}{5}$
• B. $\frac{3}{5}$
• C. $0$
• D. $1$

Answer 1

The correct option is D $1$

$A\equiv \{4,5,6\}$

$B\equiv \{1,2,3,4\}$

$\therefore A\cup B\equiv \{1,2,3,4,5,6\}$

$\therefore P(A\cup B)=\frac{6}{6}=1$