Question

A die is thrown once. Find the probability of getting a number:
i)less than $3$
ii)greater than or equal to $4$
iii)less than $8$
iv)greater than $6$.

Answer 1

A die is thrown once,

The possible outcomes $=\{1,2,3,4,5,6\}$

i.e., $n\left(S\right)=6$

(i) Probability of getting a number less than $3=\frac{n\left(E\right)}{n\left(S\right)}=\frac{2}{6}=\frac{1}{3}$

(ii) Probability of getting a number greater than or equal to $4=\frac{n\left(E\right)}{n\left(S\right)}=\frac{4}{6}=\frac{2}{3}$

(iii) Probability of getting a number less than $8=\frac{n\left(E\right)}{n\left(S\right)}=\frac{6}{6}=1$

(iv) Probability of getting a number greater than $6=\frac{n\left(E\right)}{n\left(S\right)}=\frac{0}{6}=0$