Question

A die is thrown once. Find the probability of getting.
A number lying between $2$ and $6$

Answer 1

Total outcomes that can occur are $1,2,3,4,5,6$

Number of possible outcomes of a dice$=6$

Numbers lying between $2$ and $6=3,4,5$

Total numbers lying between $2$ and $6=3$

Probability of getting a number lying between $2$ and $6$

$=$(Number of outcomes where there is a number between $2$ and $6)÷$(Total number of outcomes)

$=\frac{3}{6}=\frac{1}{2}$