Question

A die is thrown once. Find the probability of getting a prime number.

Answer 1

Find the required probability:

We have,

Possible numbers of events on throwing a dice $=6$
Numbers on dice$=1,2,3,4,5,6$

Prime numbers$=2,3,5$

Favourable number of outcomes$=3$

Probability that it will be a prime number$\begin{array}{rcl}& =& \frac{\mathrm{number}\mathrm{of}\mathrm{favourable}\mathrm{outcomes}}{\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{outcomes}}\end{array}$

$\begin{array}{rcl}& =& \frac{3}{6}\\ & =& \frac{1}{2}\end{array}$

Hence, probability that it will be a prime number is $\frac{1}{2}$.