A die is thrown once, the probability of getting a prime number is 1/m.
Value of m is

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Can't determine

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Solution

The correct option is D 2
Prime numbers on a die are 2,3 and 5
So, P(getting a prime number) = 3/6 = 1/2

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A die is thrown once. The probability of getting a prime number is
(a) $\frac{2}{3}$ (b) $\frac{1}{3}$ (c) $\frac{1}{2}$ (d) $\frac{1}{6}$

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