Question

A die is thrown once. What is the probability of getting a number lying between 1 and 6?

• A. $1$
• B. $\frac{5}{6}$
• C. $\frac{2}{3}$
• D. $\frac{1}{2}$

Answer 1

Answer: (C)

$\frac{2}{3}$

Total possible outcomes for a single die $=6$

$\therefore$ numbers lying between 1 and 6 $=4$

$i.e2,3,4and5$.

$P\left(A\right)=\frac{Numberoffavorableoutcomes}{TotalNumberofpossibleoutcomes}$

$\therefore P\left(A\right)=\frac{4}{6}=\frac{2}{3}$

hence option $C$ is correct.