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Certain Event and Impossible Event

A die is thro...

Question

A die is thrown once. What is the probability that the

¹/₂, ²/₃

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¹/₂ , ¹/₃

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¹/₂ , ¹/₈

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²/₃, ²/₃

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²/₃, 1

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Solution

The correct option is A
¹/₂, ²/₃

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Similar questions

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 1 & 1 & 5 2 & 4 & 7 \end{matrix} ⎤ ⎥ ⎦

a_{31} A_{31} + a_{32} A_{32} + a_{33} A_{33}

1 + \frac{2}{3} (\frac{1}{8}) + \frac{2 \times 5}{3 \times 6} {(\frac{1}{8})}^{2} + \frac{2 \times 5 \times 8}{3 \times 6 \times 9} {(\frac{1}{8})}^{3} + . . . .

\frac{x}{2} = \frac{y}{- 3} = \frac{z}{1}

\frac{x - 2}{3} = \frac{y - 1}{- 5} = \frac{z + 2}{5}

S = 1 + \frac{1}{(1 + 3)} (1 + 2)^{2} + \frac{1}{(1 + 3 + 5)} (1 + 2 + 3)^{2} + \frac{1}{(1 + 3 + 5 + 7)} (1 + 2 + 3 + 4)^{2} + \dots \dots

\sqrt{3 \times 5^{- 3}} \div \sqrt[3]{3^{- 1}} \sqrt{5} \times \sqrt[6]{3 \times 5^{6}} = \frac{3}{5}

9^{3 / 2} - 3 \times 5^{0} - {(\frac{1}{81})}^{-}^{1 / 2} = 15

{(\frac{1}{4})}^{- 2} - 3 \times 8^{2 / 3} \times 4^{0} + {(\frac{9}{16})}^{- 1 / 2} = \frac{16}{3}

\frac{2^{1 / 2} \times 3^{1 / 3} \times 4^{1 / 4}}{10^{- 1 / 5} \times 5^{3 / 5}} \div \frac{3^{4 / 3} \times 5^{- 7 / 5}}{4^{- 3 / 5} \times 6} = 10

\sqrt{\frac{1}{4} + (0.01)^{- 1 / 2}} - (27)^{2 / 3} = \frac{3}{2}

\frac{2^{n} + 2^{n - 1}}{2^{n + 1} - 2^{n}} = \frac{3}{2}

{(\frac{64}{125})}^{- 2 / 3} + \frac{1}{{(\frac{256}{625})}^{1 / 4}} + (\frac{\sqrt{25}}{\sqrt[3]{64}}) = \frac{65}{16}

\frac{3^{- 3} \times 6^{2} \times \sqrt{98}}{5^{2} \times \sqrt[3]{1 / 25} \times (15) -^{4 / 3} \times 3^{1 / 3}} = 28 \sqrt{2}

\frac{(0.6)^{0} - (0.1) - 1}{{(\frac{3}{8})}^{- 1} {(\frac{3}{2})}^{3} + {(- \frac{1}{3})}^{- 1}} = - \frac{3}{2}

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