The correct option is A 12
Let A be the event of getting the sum 9 and B be the event of getting at least one 4.
Then A = {(3, 6), (4, 5), (5, 4), (6, 3)}
B = {(1, 4), (2, 4), (3, 4) (4, 4), (5, 4), (6, 4),}
(4, 1), (4, 2), (4, 3), (4, 5), (4, 6)}
then A∩B=(4,5)(5,4)
∴ Required probability =P(BA)=P(A∩B)P(A)
=n(A∩B)n(A)=24=12