Question

A die is thrown twice. What is the probability that
$5$ will come up at least once?

Answer 1

Outcomes $=(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),$
$(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)$,
$(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)$
P($5$ will come up at least once)$=\frac{11}{36}$
Explanation :- $5$ will come up at least once means either of the dice gets a number $5$ on them. So possible outcomes are
$=(1,5),(2,5),(3,5),(4,5),(6,5),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),$