A die is tossed thrice. Getting an even number is considered as success. What is the variance of the binomial distribution ?

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Solution

Here, $n = 3$
p = Probability of getting an even number in a single throw of a die
$p = \frac{3}{6} = \frac{1}{2}$

And, $q = 1 - p = 1 - \frac{1}{2} = \frac{1}{2}$

Therefore,
Variance = $n p q = 3 \times \frac{1}{2} \times \frac{1}{2} = \frac{3}{4}$

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A die is tossed thrice. Getting an even number is considered as success. What is the variance of the binomial distribution ?

Here, n=3p = Probability of getting an even number in a single throw of a diep=36=12And, q=1−p=1−12=12Therefore,Variance = npq=3×12×12=34

Here, $n = 3$
p = Probability of getting an even number in a single throw of a die
$p = \frac{3}{6} = \frac{1}{2}$

And, $q = 1 - p = 1 - \frac{1}{2} = \frac{1}{2}$

Therefore,
Variance = $n p q = 3 \times \frac{1}{2} \times \frac{1}{2} = \frac{3}{4}$