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Question

A die is tossed twice. Find the probability of getting a number greater than 3 on each toss.

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Solution

S= {1 1, 1 2, 1 3, 1 4, 1 5, 1 6, 2 1, 2 2, 2 3, 2 4, 2 5, 2 6, 3 1, 3 2, 3 3, 3 4, 3 5, 3 6, 4 1, 4 2, 4 3, 4 4, 4 5, 4 6, 5 1, 5 2, 5 3, 5 4, 5 5, 5 6, 6 1, 6 2, 6 3, 6 4, 6 5, 6 6}nS= 36E=Getting a number greater than 3 on each toss =4 4, 4 5, 4 6, 5 4, 5 5, 5 6, 6 4, 6 5, 6 6nE=9PE=936 =14

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