Question

A die was rolled 60 times and the result is as follows.

Find the probability of getting
(i)1
(ii) 5
(iii) an even number.

$$\begin{array}{ccccccc}\text{Number}& 1& 2& 3& 4& 5& 6\\ \text{Frequency}& 12& 14& 9& 15& 6& 4\end{array}$$ [3 MARKS]

Answer 1

Solution :1 Mark each.

(i) Probability of getting a 1 = $\frac{12}{60}=0.2$
(ii) Probability of getting a 5 = $\frac{6}{60}=0.1$
(iii) Probability of getting an even number = $\frac{14+15+4}{60}=\frac{33}{60}=0.55$