Question

A die was thrown 80 times and the outcomes were noted as shown:

Outcome	1	2	3	4	5	6
Frequency	14	11	9	13	18	15

If the die is thrown at random, what is the probability of getting a 2?

Answer 1

Total number of trials = 80
Number of times 2 appears = 11
Let E be the event of getting 2 on the die.
∴ P( getting 2) = P(E) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{times}2\mathrm{appears}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{trials}}=\frac{11}{80}$Number of times 8 appearsTotal number of trails = 050