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Question

A dielectric slab of dielectric constant k=5 is placed between plates of parallel plate capacitor, thickness of slab is 30% of plate spacing & its area is same as that of the plates, new capacitance is C & old capacitance was C. The ratio CC is approximately equal to

A
54
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B
35
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C
75
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D
43
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Solution

The correct option is D 43
If dielectric slab is placed in between the plates & slab plane is parallel to plane of plates then
C=0At/k=0A0.7d1+0.3d5=0A0.7d+0.06d
=0A0.76d=40A3d
=4C3

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