MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Capacitance of Parallel Plate Capacitor

.A dielectric...

Question

.A dielectric slab of dielectric constant K is placed between the plates of a parallel plate capacitor carryingcharge q. The induced charge q' on the surface of slab is given by(1)q'=q-q/K (2)q'=-q+q/K (3)q'=q(1/K+1) (4)q'=-q(1+1/K)

Open in App

Solution

Suggest Corrections

thumbs-up

78

Similar questions

Q. A parallel- plate capacitor is placed in such a way that its plates are horizontal and lower plate is dipped into a liquid of dielectric constant

k

ρ

. Charge on plates of capacitor is

Q

- Q

+ Q

is charge on upper plate]

Q. A dielectric slab is inserted between the plates of a capacitor. The charge on the capacitor is

Q

and the magnitude of the induced charge on each surface of the dielectric is

Q^{'}

Q. In an isolated, charged, parallel plate air capacitor, the surface charge density on each plate has a magnitude

σ

. A dielectric slab with dielectric constant K is now introduced between the plates. The induced charge per unit area on the surface of the dielectric will be :

Q. Two identical capacitors 1 and 2 connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant K as shown. If

Q_{1}

is the charge on each capacitor before removing the slab and

Q_{2}

is the charge on each capacitor after
moving the slab, then the correct relation between

Q_{1}

Q_{2}

Q. A parallel- plate capacitor is placed in such a way that its plates are horizontal and lower plate is dipped into a liquid of dielectric constant

k

ρ

. Charge on plates of capacitor is

Q

- Q

+ Q

is charge on upper plate]

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Capacitance of a Parallel Plate Capacitor

PHYSICS

Watch in App

explore_more_icon

Explore more

Capacitance of Parallel Plate Capacitor

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon