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Question

.A dielectric slab of dielectric constant K is placed between the plates of a parallel plate capacitor carryingcharge q. The induced charge q' on the surface of slab is given by(1)q'=q-q/K (2)q'=-q+q/K (3)q'=q(1/K+1) (4)q'=-q(1+1/K)

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Solution

99996163705-0-0

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Capacitance of a Parallel Plate Capacitor
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