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Question

A dielectric slab of dielectric constant K is placed between the plates of parallel plate capacitor carrying charge q the induced charge q' on the surface of slab is given by 1)q'=q-q/k 2)q'=-q+q/k 3)q'=q(1/k+1) 4)q'=-q(1+1/k)

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Solution

99996119312-0-0

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Capacitance of a Parallel Plate Capacitor
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