Question

A dielectric slab of thickness d is inserted in a parallel plate capacitor where negative plate is at $x=0$ and positive plate is at $x=3d$. The slab is equidistant from the plates. The capacitor is given some charge. As x goes from $0$ to $3d$.

• A. The magnitude of electric field remains the same.
• B. The direction of electric field remain the same.
• C. The electric potential increases continuously.
• D. The electric potential increase at first then decrease and again increase.

Answer 1

Answer: (B), (C)

The direction of electric field remain the same.
The electric potential increases continuously.

After inserting dielectric slab electric field will change because inside slab $E=\frac{E_0}{K}$.where k is the dielectric constant.
but field direction will be same. As the potential is a continuous function of x, potential will increase continuously.
Ans: $\left(B\right),\left(C\right)$