Question

A diesel engine develops a power of $90W$ at $\frac{600}{\pi }$ rpm. The torque it can exert at the angular speed is (in N-m)

• A. $4.5$
• B. $45$
• C. $0.45$
• D. $9\pi$

Answer 1

The correct option is A $4.5$

Torque=Power/angular velocity

angular velocity$=\left(600/\pi \right)\times \left(2\pi /60\right)=20$

$=\frac{90}{20}=4.5N-m$