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Question

A difference of $$2.3 eV$$ separates two energy levels in an atom. What is the frequency of radiation emitted when the atom makes a transition from the upper level to the lower level?


Solution

Given: The difference in energy between the two energy levels is $$2.3eV$$.

To find: The frequency of radiation emitted when the atom makes a transition between the energy levels.

The energy between the energy levels is 
$$E=2.3eV\\\Rightarrow2.3\times1.6\times10^{-19} J$$

The frequency of the radiations emitted during transition is:
$$E=h\nu$$
$$\nu=\dfrac hE$$
$$\Rightarrow\dfrac{6.626\times10^{-34}}{2.3\times1.6\times10^{-19}}$$

$$\Rightarrow5.5\times10^{14}Hz$$

Physics
NCERT
Standard XII

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