Question

A difference of temperature of ${25}^{\circ }C$ is equivalent to a difference of

• A. ${45}^{\circ }F$
• B. ${72}^{\circ }F$
• C. ${32}^{\circ }F$
• D. ${25}^{\circ }F$

Answer 1

The correct option is A ${45}^{\circ }F$

relation between Fahrenheit to Celsius is

$C=\frac{5(F-32)}{9}$

$C_1-C_2=\frac{5(F_1-32)/9-5(F_2-32)}{9}$

$\Rightarrow 25=\frac{5(F_1-F_2)}{9}$

$\Delta F={45}^{o}F$