A digit is chosen at random from the digits 1 to 9. The probability that the digit is even is

\frac{4}{9}

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\frac{5}{9}

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\frac{1}{9}

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\frac{1}{2}

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Solution

The correct option is C $\frac{4}{9}$
Total number of cases $= 9$
Number of favourable cases (the digit is even) ${2, 4, 6, 8} = 4$
$∴$ P (digit is even) = $\frac{4}{9}$

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A book has pages numbered from 1 to 100. If a page is chosen at random, what is the probability that the sum of the digits on the page is 9?

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