A dihaloalkane $^{'} X^{'}$ , having formula $C_{3} H_{6} C l_{2}$ , on hydrolysis gives a compound, that can reduce Tollen's reagent. The compound $^{'} X^{'}$ is

1, 2

-dichloropropane

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1, 1

-dichloropropane

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1, 3

-dichloropropane

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2, 2

-dichloropropane

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Solution

The correct option is C $1, 1$ -dichloropropane
Since, the obtained compound reduces Tollen's reagent, it must be an aldehyde. Thus, it is obvious that both the $- C l$ atoms are present at $C_{1}$ . Hence, the compound 'X' is $1, 1$ - dichloropropane and the reations are as follows.

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A dihaloalkane ′X′, having formula C3H6Cl2, on hydrolysis gives a compound, that can reduce Tollen's reagent. The compound ′X′ is

The correct option is C 1,1-dichloropropaneSince, the obtained compound reduces Tollen's reagent, it must be an aldehyde. Thus, it is obvious that both the −Cl atoms are present at C1. Hence, the compound 'X' is 1,1- dichloropropane and the reations are as follows.

A dihaloalkane $^{'} X^{'}$ , having formula $C_{3} H_{6} C l_{2}$ , on hydrolysis gives a compound, that can reduce Tollen's reagent. The compound $^{'} X^{'}$ is

The correct option is C $1, 1$ -dichloropropane
Since, the obtained compound reduces Tollen's reagent, it must be an aldehyde. Thus, it is obvious that both the $- C l$ atoms are present at $C_{1}$ . Hence, the compound 'X' is $1, 1$ - dichloropropane and the reations are as follows.