A dihalogen derivative $^{'} X^{'}$ of a hydrocarbon with three carbon atoms reacts with alcoholic KOH and produces another hydrocarbon which forms a red precipitate with ammoniacal $C u_{2} C l_{2}$ . $^{'} X^{'}$ gives an aldehyde on reaction with aqueous KOH.

1,3-Dichloropropane

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1,2-Dichloropropane

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2,2- Dichloropropane

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1,1-Dichloropropane

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Solution

The correct option is D 1,1-Dichloropropane

$The compound ( x ) is 1,1-Dichloropropane$

Red precipitate with ammoniacal $C u_{2} C l_{2}$ is a characteristic reaction of alk-1-yne. That means the hydrocarbon is 1 - propyne.
Reaction with aqueous KOH gives aldehyde that means the two halides are attached to the same carbon that is carbon number one.
The above reason indicates that the compound ( x ) is $1, 1 - D i c h l o r o p r o p a n e$

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A dihalogen derivative ′X′ of a hydrocarbon with three carbon atoms reacts with alcoholic KOH and produces another hydrocarbon which forms a red precipitate with ammoniacal Cu2Cl2. ′X′ gives an aldehyde on reaction with aqueous KOH.

A dihalogen derivative $^{'} X^{'}$ of a hydrocarbon with three carbon atoms reacts with alcoholic KOH and produces another hydrocarbon which forms a red precipitate with ammoniacal $C u_{2} C l_{2}$ . $^{'} X^{'}$ gives an aldehyde on reaction with aqueous KOH.