A-dil- HNO3- B-NO-S-H20B C -excessNH4OH-Deep blue solution-Identify -B-

Copper sulphides on reacting with dil.HNO_3 forms nitrates, which on heating nbsp;sulphur is oxidised to sulphate and copper sulphate is formed. nbsp; Copp ...

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Byju's Answer

Standard XII

Chemistry

Oxidizing and Reducing Character of Halogens

A+dil. HNO3→ ...

Question

$A + d i l . H N O_{3} \to B + N O + S + H_{2} 0$
$B Δ - \to C + N H_{4} O H e x c e s s \to Deep blue solution$ ;
Identify 'B'.

P b {(N O_{3})}_{2}

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B i {(N O_{3})}_{3}

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C u {(N O_{3})}_{2}

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A r {(N O_{3})}_{3}

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Solution

The correct option is C $C u {(N O_{3})}_{2}$
Copper sulphides on reacting with $d i l . H N O_{3}$ forms nitrates, which on heating sulphur is oxidised to sulphate and copper sulphate is formed.

Copper sulphate on reacting with excess of ammonium hydroxide forms a soluble complex, tetramminecopper (II) complex which is deep blue in colour.

$C u S + 8 H N O_{3} \to 3 C u (N O_{3})_{2} + 2 N O + 3 S + 4 H_{2} O$
$S + 2 H N O_{3} \to H_{2} N O_{3} + 2 N O 2 C u^{2 +} + S O_{3}^{2 -} + 2 N H_{3} + 2 H_{2} O \to C u (O H)_{2} . C u S O_{4} + 2 N H_{4}^{+} C u (O H)_{2} . C u S O_{4} + 8 N H_{3} \to 2 [C u (N H_{3})_{4}] S O_{4} t e t r a m m i n e c o p p e r (I I) s u l p h a t e D e e p b l u e + 2 O H^{-} + S O_{4}^{2 -}$

Only $C u$ ion forms deep blue complex with ammonium hydroxide.

Hence, option (c) is correct.

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Similar questions

Q. Sodium carbonate extract of the salt is acidified with

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and

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A+dil.HNO3→B+NO+S+H20 BΔ−→C+NH4OHexcess→Deep blue solution; Identify 'B'.

$A + d i l . H N O_{3} \to B + N O + S + H_{2} 0$
$B Δ - \to C + N H_{4} O H e x c e s s \to Deep blue solution$ ;
Identify 'B'.