A dilute aqueous solution of $C u S O_{4}$ is electrolyzed using platinum electrodes. The products at the anode and cathode are:

O_{2}, H_{2}

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H_{2}, O_{2}

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O_{2}, C u

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S_{2} O_{8}^{-}, H_{2}

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Solution

The correct option is A $O_{2}, H_{2}$
$C u S O_{4} ⟶ {C u}^{2 +} + S O_{4}^{2 -}$
Anode:

$2 H_{2} O ⟶ 4 e^{-} + 4 H^{+} + O_{2} (1 \cdot 23 V)$
At cathode :
$C u^{+ 2} + 2 e^{-} ⟶ C u (0.34 v)$

$H^{+} + e^{θ} ⟶ \frac{1}{2} H_{2} (0.0 v)$
At anode $= O_{2}$
At cathode $= C u$

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