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Question

A dilute solution Contains “x” moles of solute “A” in 1 kg of solvent with molal elevation constant kb. The solute dimerises in the solution according to the following equation. The degree of association is α. 2AA2
The degree of association is equal to

A
α=(Kb. xΔTb)ΔTb.2
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B
α=(Kb. xΔTb)Kb.x
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C
α=2.ΔTbKb.x+2
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D
α=ΔTb2.Kb.x
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Solution

The correct option is B α=(Kb. xΔTb)Kb.x
A dilute solution Contains “x” moles of solute “A” in 1 kg of solvent with molal elevation constant kb. The solute dimerises in the solution according to the following equation. The degree of association is α.
2AA2
ΔTb=i×Kb×x1ΔTbKb.x=122=1ΔTbKbx=2(1ΔTbKb.x)=2(Kb.xΔTbKb.x)

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