A dilute solution is prepared by adding $500 m L$ of water to $50 m L$ of $0.10 M H N O_{3} (a q)$ . Determine the concentration of hydrogen ion.

0.0010 M

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0.0050 M

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0.010 M

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0.050 M

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1.0 M

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Solution

The correct option is C $0.010 M$
$M_{1} V_{1} = M_{2} V_{2}$

$M_{1} = 0.10 M$

$V_{1} = 50 m L$

$M_{2} = ?$

$V_{2} = 50 + 500 = 550 m L$

$0.10 M \times 50 m L = M_{2} \times 550 m L$

$M_{2} = 0.010 M$

Hence, the hydrogen ion concentration in the diluted solution is $0.010 M$ .

Hence, the correct option is $C$

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