Question

A dilute solution of $H_2{SO}_4$ is made by adding $5mL$ of $3N$ $H_2{SO}_4$ to $245mL$ of water. Calculate the normality and molarity of the solution.

Answer 1

We know,

$N_1{V}_1=N_2{V}_2$

$N_1=3$ $N$

$N_2=x$

$V_1=5$ $ml$

$V_2=245$ $ml$

$\therefore N_1{V}_1=N_2{V}_2$

$\Rightarrow 3\left(5\right)=245\left(x\right)$

$\Rightarrow x=0.0612$ $N$

$\therefore$ Normality $=0.0612$ $N$

Now, Basicity of $H_{2}S{O}_4=2$

$\frac{Normality}{Molarity}=Basicity$

$\Rightarrow \frac{0.0612}{Molarity}=2$

$\Rightarrow Molarity=0.0306$ $M$