A dilute solution of sulphuric acid during electrolysis liberate O $_{2}$ gas at the anode.

True

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False

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Solution

The correct option is A True
Because ${S O}_{4}^{2 -}$ mobility is very less as compared to ${O H}^{-}$ . So instead of ${S O}_{4}^{2 -}, {O H}^{-}$ undergo oxidation to form $O_{2}$ at anode.
Also oxidation potential of ${O H}^{-}$ is more than ${S O}_{4}^{2 -}$

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Similar questions

Q. During the electrolysis of dilute sulphuric acid, the following process is possible at anode.

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c) Oxygen and hydrogen are produced at the anode and cathode during the electrolysis of dilute aqueous solution of $H_{2} S O_{4}$ .

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A dilute solution of sulphuric acid during electrolysis liberate O2 gas at the anode.

The correct option is A TrueBecause SO2−4 mobility is very less as compared to OH− . So instead of SO2−4,OH− undergo oxidation to form O2 at anode. Also oxidation potential of OH− is more than SO2−4

A dilute solution of sulphuric acid during electrolysis liberate O $_{2}$ gas at the anode.

The correct option is A True
Because ${S O}_{4}^{2 -}$ mobility is very less as compared to ${O H}^{-}$ . So instead of ${S O}_{4}^{2 -}, {O H}^{-}$ undergo oxidation to form $O_{2}$ at anode.
Also oxidation potential of ${O H}^{-}$ is more than ${S O}_{4}^{2 -}$