A dinner at a restaurant costs $R s 1095$ for $10$ people. How many people can dine with $R s 1971$ ?

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Solution

Rs. $1095 \to$ $10$ people UNITARY MGTHOD
Rs. $1 \to$ $10 / 1095$
Rs. $1971 \to$ $\frac{10}{1095} \times 1971 = 180$ people.

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A dinner at a restaurant costs Rs 1095 for 10 people. How many people can dine with Rs 1971?

Rs. 1095→ 10 people UNITARY MGTHODRs. 1→ 10/1095Rs. 1971→ 101095×1971=180 people.

A dinner at a restaurant costs $R s 1095$ for $10$ people. How many people can dine with $R s 1971$ ?

Rs. $1095 \to$ $10$ people UNITARY MGTHOD
Rs. $1 \to$ $10 / 1095$
Rs. $1971 \to$ $\frac{10}{1095} \times 1971 = 180$ people.