Question

# A diode detector is used to detect an amplitude modulated wave of $60%$ modulation by using a condenser of capacity $250pF$ in parallel with a load resistance $100$ kilo ohm. Find the maximum modulated frequency which could be detected by it.

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Solution

## Step 1. Given data:Resistance $\left(R\right)=100×{10}^{3}\Omega$Capacitance $\left(C\right)=250×{10}^{-12}F$Modulation, $\mu =0.6$Step 2. Formula used:For a combination of resistance and capacitance,Frequency can be given as: $f=\frac{1}{2\mathrm{\pi \mu RC}}$, where $R=$resistance, $C=$capacitence, $\mu =$modulation.Step 3. Calculating frequencyPutting the given values in the above equation, we getFrequency $\left(f\right)=\frac{1}{2×3.14×0.6×100×{10}^{3}×250×{10}^{-12}}=10.6167KHz$Hence, the maximum modulated frequency that could be detected by it is $10.6167KHz$.

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