Question

A diode is connected to $220v$ (rms) ac in series with a capacitor as shown in figure. The voltage across the capacitor is :

• A. $220V$
• B. $110V$
• C. $311.1V$
• D. $220\sqrt{2}$

Answer 1

The correct option is A $220V$

Solution

REF.Image

The diode will rectify

the voltage from AC

to DC. Thus,

We have,

$V_{1}rms=\sqrt{\frac{{\int }_0^T{V}_1^2.dt}{T}}=220$

In $V_2-t$,

$V_{2}rms=\sqrt{\frac{{\int }_0^T{V}_2^2-dt}{T}}=\sqrt{\frac{{\int }_0^T{V}_1^2.dt}{2T}}$

$V_{2}rms=\frac{220}{\sqrt{2}}$

$V_{2}max=V_{2}rms\sqrt{2}=220V$

Option - A is correct.