Question

A dip circle is at right angle to the magnetic meridian. The apparent dip angle is

• A. $0^o$
• B. ${30}^o$
• C. ${60}^o$
• D. ${90}^o$

Answer 1

Answer: (D)

${90}^o$

Relation between apparent dip and angle with the magnetic meridian is
$\cot {\alpha }_1=\cot \alpha \times \cos {\alpha }_2$
${\alpha }_1$ is the apparent dip
${\alpha }_2$ is the angle made with the magnetic meridian
$\alpha$ is the true dip
$\cot {\alpha }_1=\cot \alpha \times \cos {90}^o$
$\cot {\alpha }_1=0$
${\alpha }_1={90}^o$