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Question

A dip needle shows an angle of dip θ in a place which is in the magnetic meridian. Now, the dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip θ1. Value of tanθ1/tanθ is :


A
1cosx
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B
1sinx
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C
1tanx
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D
cosx
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Solution

The correct option is A 1cosx
assume horizontal component of field in magnetic meridian is H and vertical component of magnetic field is V
If the dip circle makes an angle x with the magnetic meridian , apparent horizontal component of field Ha=Hcosx
tanθ1=VHa
θ1 is the new dip angle (apparent dip angle)
tanθ1=VHcosx
tanθ=VH , θ is the true dip angle
tanθ1=secx×tanθ

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