A dip needle shows an angle of dip θ in a place which is in the magnetic meridian. Now, the dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip θ1. Value of tanθ1/tanθ is :
A
1cosx
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B
1sinx
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C
1tanx
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D
cosx
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Solution
The correct option is A1cosx assume horizontal component of field in magnetic meridian is H and vertical component of magnetic field is V If the dip circle makes an angle x with the magnetic meridian , apparent horizontal component of field Ha=Hcosx tanθ1=VHa θ1 is the new dip angle (apparent dip angle) tanθ1=VHcosx tanθ=VH , θ is the true dip angle tanθ1=secx×tanθ