Question

A dip of circle is so set that it moves freely in the magnetic meridian. In this position, the angle of dip is ${40}^0$. Now, the dip circle is rotated so that the plane in which the needle moves makes an angle of ${30}^0$ with the magnetic meridian. In this position, the needle will dip by an angle of

• A. ${40}^0$
• B. ${30}^0$
• C. More than ${40}^0$
• D. Less than ${40}^0$

Answer 1

The correct option is C More than ${40}^0$

$\tan {\theta }^{‘}=\frac{\tan \theta }{\cos \alpha }{\theta }^{‘}>\theta {\theta }^{‘}>{40}^{\circ }$

Hence option 'C' is correct.