A dip placed in a plane which is perpendicular to magnetic meridian will remain

Parallel to surface of earth

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At angle

{11.2}^{\circ}

with surface of earth

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Vertical

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At angle

{11.2}^{\circ}

with vertical

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Solution

The correct option is C Vertical
In a plane $⊥$ to magnetic meridian, horizontal component becomes zero, hence needle point is vertical

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Similar questions

Q. A dip placed in a plane which is perpendicular to magnetic meridian will remain

Q. In a vertical plane

p_{1}

making angle

30^{o}

with magnetic meridian, apparent angle of dip in vertical plane

p_{2}

60^{o}

, which is perpendicular to plane

p_{1}

is:

The angle of dip at a place is $δ$ . If the dip is measured in a plane making an angle $θ$ with the magnetic meridian, the apparent angle of dip $δ_{1}$ will be :

Q. If a dip circle is placed in a vertical plane at an angle of

30^{o -}

to the magnetic meridian, the dip needle makes an angle of

45^{o -}

with the horizontal. The real dip at that place is?

Q. The true value of angle of dip at a place is

60^{\circ}

, the apparent dip in a plane inclined at an angle of

30^{\circ}

with magnetic meridian is

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A dip placed in a plane which is perpendicular to magnetic meridian will remain

The correct option is C VerticalIn a plane ⊥ to magnetic meridian, horizontal component becomes zero, hence needle point is vertical

The correct option is C Vertical
In a plane $⊥$ to magnetic meridian, horizontal component becomes zero, hence needle point is vertical